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Construct the expression for Ka for the weak acid CH3COOH.
Construct the expression for Ka for the weak acid CH3COOH.A) Ka = [H+][CH3COO-]/[CH3COOH]
B) Ka = [H2CO3]/[HCO3-]
C) Ka = [H2O]/[OH-]
D) Ka = [CH3COOH]/[CH3COO-]
Final answer:The correct expression for the acid dissociation constant (Ka) for the weak acid CH3COOH is A) Ka = [H+][CH3COO-]/[CH3COOH].Explanation:The expression for Ka for the weak acid CH3COOH is Ka = [H+][CH3COO-]/[CH3COOH]. The weak acid partially dissociates in water, and the equilibrium constant, Ka, is the ratio of the concentration of the products to the concentration of the reactants. Hence, the correct answer is A) Ka = [H+][CH3COO-]/[CH3COOH]. The concentration of hydronium ions [H3O+] can be used interchangeably with [H+] when determining the pH of the solution based on the acid dissociation....
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