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Constants for water hvap 40.65 kj/mol hf -285.83 kj/mol hfusion 6.03 kj/mol specific heat 4.186 j/gc molar mass 18.02 g how much energy is consumed by thawing 4.3 g ice? a. 4.3 g 1 mol/18.02 g 40.65 kj/mol b. 4.3 g 1 mol/18.02 g 4.186 kj/mol c. 4.3 g 1 mol/18.02 g (-285.83) kj/mol d. 4.3 g 1 mol/18.02 g 6.03 kj/mol
Constants for water hvap 40.65 kj/mol hf -285.83 kj/mol hfusion 6.03 kj/mol specific heat 4.186 j/gc molar mass 18.02 g how much energy is consumed by thawing 4.3 g ice? a. 4.3 g 1 mol/18.02 g 40.65 kj/mol b. 4.3 g 1 mol/18.02 g 4.186 kj/mol c. 4.3 g 1 mol/18.02 g (-285.83) kj/mol d. 4.3 g 1 mol/18.02 g 6.03 kj/mol
Final answer:The energy consumed during the thawing of 4.3g ice can be calculated using the heat fusion of water, resulting in approximately 1.14 kJ, making option D: 4.3 g 1 mol/18.02 g 6.03 kJ/mol, the correct one.Explanation:This question is about calculating theenergyconsumed in the process of thawing ice. The phase transition from solid ice to liquid water requires energy, which we calculate using the heat of fusion, given the amount of ice, and its molar mass.To determine this, we can use the provided information: the heat of fusion (hfusion) for water is 6.03 kJ/mol, the mass of ice is 4.3 g, and the molar mass of water is 18.02 g/mol. We first convert the grams of ice into moles by dividing by the molar mass. We then multiply by the heat of fusion.Energy consumed = (4.3g / 18.02 g/mol) * 6.03 kJ/mol = 1.14 kJSo, the option D: 4.3 g 1 mol/18.02 g 6.03 kJ/mol, is the correct one.Learn more about Thawing Ice Energy Consumption here:brainly.com/question/32418980#SPJ11...