is the equation of the line that is perpendicular to this line and passes through the point (6, -2)y = 7x - 44 equation of the line that is parallel to this line and passes through the point (6, -2)Solution:Given that line is:y = 7x - 9The equation of line in slope intercept form is given as:y = mx + b ------ eqn 1Where, "m" is the slope of line and "b" is the y interceptOn comparing eqn 1 with y = 7x - 9 we get,m = 7Find the equation of the line that is perpendicular to this line and passes through the point (6, -2)We know that,Product of slope of a line and slope of line perpendicular to given is always -1Therefore,Now find the equation of line:Thus the equation of line perpendicular to given line is foundFind the equation of the line that is parallel to this line and passes through the point (6, -2)Slopes of parallel lines are equalTherefore,  m = 7Substitute m = 7 and (x, y) = (6, -2) in eqn 1-2 = 7(6) + b-2 = 42 + bb = -44Substitute m = 7 and b = -44 in eqn 1y = 7x - 44Thus equation of line parallel to given line is found...

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