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Consider a triangle ABC like the one below. Suppose that a=34,b=19, and c=22. (The figure is not drawn to scale.) Solve the triangle. Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth. If there is more than one solution, use the button labeled "or".
Consider a triangle ABC like the one below. Suppose that a=34,b=19, and c=22. (The figure is not drawn to scale.) Solve the triangle. Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth. If there is more than one solution, use the button labeled "or".
ThetriangleABC has angles A ≈ 40.1 degrees, B ≈ 29.9 degrees, and C ≈ 110 degrees, with side lengths a = 34, b = 19, and c = 22.To solve the triangle ABC with given side lengths a = 34, b = 19, and c = 22, we can use the Law ofCosinesand Law ofSines.1. To find angle A, we can use the Law of Cosines:cos(A) = (b^2 + c^2 - a^2) / (2bc)cos(A) = (19^2 + 22^2 - 34^2) / (2 * 19 * 22)cos(A) = (361 + 484 - 1156) / (836)cos(A) = (689) / (836)A ≈ 40.1 degrees2. To find angle B, we can use the Law of Cosines:cos(B) = (a^2 + c^2 - b^2) / (2ac)cos(B) = (34^2 + 22^2 - 19^2) / (2 * 34 * 22)cos(B) = (1156 + 484 - 361) / (1484)cos(B) = (1279) / (1484)B ≈ 29.9 degrees3. To find angle C, we can use the fact that the sum ofanglesin a triangle is 180 degrees:C = 180 - A - BC ≈ 180 - 40.1 - 29.9C ≈ 110 degreesFor more such questions ontrianglebrainly.com/question/25215131#SPJ8...