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Carbon is allowed to diffuse through a steel plate 15 mm thick. The concentrations of carbon at the two faces are 0.65 and 0.30 kg C/m3 Fe, which are maintained constant. If the preexponential and activation energy are 6.2 x 10-7 m2/s and 80,000 J/mol, respectively, compute the temperature at which the diffusion flux is 1.43 x 10-9kg/m2-s.
Carbon is allowed to diffuse through a steel plate 15 mm thick. The concentrations of carbon at the two faces are 0.65 and 0.30 kg C/m3 Fe, which are maintained constant. If the preexponential and activation energy are 6.2 x 10-7 m2/s and 80,000 J/mol, respectively, compute the temperature at which the diffusion flux is 1.43 x 10-9kg/m2-s.
Thetemperatureat which the diffusionfluxis 1.43 ×·s is 804.53 Kelvin (K).To compute thetemperatureat which the diffusionfluxis 1.43 ×·s, use theArrheniusequation for diffusion:Where:change inconcentration= 0.65 kgFe - 0.30 kgFe.Thicknessof the steel plate = 15 mm = 0.015 m.The diffusioncoefficientD can be calculated using theArrheniusequation:Rearrangethe equation as follows:Now,plugin the values:=So, thetemperatureis 804.53 Kelvin (K).Learn more aboutDiffusionhere:brainly.com/question/33792345#SPJ12...
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