Final answer:To calculate the pH of theresultantsolution when adding HCl to NaOH, note that HCl and NaOH react to form water and NaCl. Calculate the number of moles for each reactant, then calculate the remaining molarity when subtracting the acid moles from the base moles. Lastly, use the formula: 14-log[OH-] to find the pH of the resulting solution.Explanation:In order to determine the pH of the resulting solution, you'll need to first identify the number of moles of each reactant involved in the chemical reaction. These reactants are Hydrochloric Acid (HCl) and Sodium Hydroxide (NaOH), which are typical examples of strong acid and strong base. They react together to form water and sodium chloride, following this chemical equation: HCl(aq) + NaOH(aq) -> H2O(l) + NaCl(aq).For the first scenario, (a) with 32.0 mL of 0.320 M HCl(aq) added to 42.0 mL of 0.320 M NaOH(aq). The number of moles for HCl and NaOH can be calculated bymultiplyingthe given molarity by the volume (in liter). For HCl that would be 0.320 M * 0.032 L = 0.01024 moles, and for NaOH it would be 0.320 M * 0.042 L = 0.01344 moles. Here, since there are more moles of NaOH present, the solution resulting from the reaction would be basic. You would then calculate the remaining moles of NaOH, subtracting the moles ofHClfrom the moles of NaOH. Then, calculate the new molarity, dividing the remaining moles of NaOH by the total volume in liters, and finally, calculate the pH using the formula: 14-log[OH-].For the second scenario, (b) with 32.0 mL of 0.320 M HCl(aq) added to 22.0 mL of 0.420 M NaOH(aq), you would follow the same process. Istronglyencourage you to attempt scenario (b) by yourself for practice.Learn more about pH Calculation here:brainly.com/question/34432529#SPJ11...

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