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Calculate the number of coulombs of positive charge in 250 cm³ of (neutral) water. (Hint: A hydrogen atom contains one proton; an oxygen atom contains eight protons.) Calculate the number of coulombs of positive charge in 250 cm³ of (neutral) water.
Calculate the number of coulombs of positive charge in 250 cm³ of (neutral) water. (Hint: A hydrogen atom contains one proton; an oxygen atom contains eight protons.) Calculate the number of coulombs of positive charge in 250 cm³ of (neutral) water.
Final answer:The total positive charge in 250 cm³ of neutral water is approximately 1.34 × 10⁷ Coulombs, calculated by first determining the number of water molecules in the given volume, and then multiplying by the charge per molecule due to protons.Explanation:To calculate the number of coulombs of positive charge in 250 cm³ of (neutral) water, we first estimate the number of water molecules present in this volume.Since 1 mole of water has a volume of about 18 cm³, 250 cm³ of water would contain about 13.89 moles (250/18) of water molecules.Given that 1 mole of water molecules consists of 6.02 × 10²³ molecules, 13.89 moles will contain approximately 8.36 × 10²´ molecules of water.Each water molecule (H₂O) is composed of two hydrogen atoms and one oxygen atom. Knowing that a hydrogen atom contains one proton and an oxygen atom contains eight protons, each water molecule will have a total of ten protons. Therefore, the total positive charge, contributed by the protons in 250 cm³ of water, can be calculated by multiplying the number of water molecules by the total charge per molecule.Since the charge of one proton is approximately +1.6022 × 10⁻¹⁹ Coulombs and each water molecule has ten protons, the charge per molecule is +1.6022 × 10⁻¹⁸ Coulombs.Thus, the total positive charge in 250 cm³ of water is about8.36 × 10²´ molecules × 1.6022 × 10⁻¹⁸ Coulombs/molecule= 1.34 × 10⁷ Coulombs....