To calculate thenuclearbinding energy of 5525 Mn 2555 Mn, we need to use the formula E = mc^2, where E is the energy, m is the mass, and c is the speed of light.First, we need to convert the given masses into kilograms. The atomic mass of manganese (Mn) is approximately 55.845 grams/mol. Therefore, the mass of 5525 Mn is 5525 grams/mol, which is equal to 5.525 kilograms/mol. Similarly, the mass of 2555 Mn is 2555 grams/mol, which is equal to 2.555 kilograms/mol.Next, we calculate the energy using the formula E = mc^2. The speed of light (c) is approximately 3 x 10^8 meters/second.For 5525 Mn:E = (5.525 kg/mol) * (3 x 10^8 m/s)^2E = 4.9725 x 10^17 kg * m^2/s^2For 2555 Mn:E = (2.555 kg/mol) * (3 x 10^8 m/s)^2E = 2.2995 x 10^17 kg * m^2/s^2To find the nuclear binding energy, we subtract the energy of 2555 Mn from the energy of 5525 Mn:Nuclear binding energy = (4.9725 x 10^17 kg * m^2/s^2) - (2.2995 x 10^17 kg * m^2/s^2)Nuclear binding energy = 2.673 x 10^17 kg * m^2/s^2To express the answer numerically in joules, we need to convert kg * m^2/s^2 to joules. Since 1 Joule is equal to 1 kg * m^2/s^2, the nuclear binding energy is 2.673 x 10^17 Joules.Therefore, the nuclear binding energy of 5525 Mn 2555 Mn is more than 120 Joules, specifically 2.673 x 10^17 Joules.To know more about thatnuclearvisit:brainly.com/question/13090058#SPJ11...

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