Answer:2Al   +   6HBr    →   2AlBr₃   +   3H₂Explanation:2Al   +   6HBr    →   2AlBr₃   +   3H₂2 Al in reactant side2 Al in product side6 Br in reactant side6 (2x3) Br in reactant side6 H in reactant side6 H in product side (3x2)...

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