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The answers to your question are as listed belowA) If we move the apple0.3 FR awayfrom the planet the value of h is ;0.825 RB) If we move the apple0.3 FR intothe tunnel the distance is ;0.7 RAssumptions :mass of apple = mForce on apple at planet surface == GMm / R² --- ( 1 )Determine th value of ha) Applying equation ( 1 )gravitational force of apple at h = 0.3 FRtherefore equation ( 1 ) becomes0.3 FR = GMm / (R + h)² ----- ( 2 )divide both sides of equation by1 / 0.3 = ( R + h )²/ R²therefore :h = 0.825 Rb) When we go into thetunnelApplying the relation below0.3 FR = G *4/3 π *( R - h )³* dm / (R-h)² -- ( 3 )where : d = density of planetresolvingequation ( 3 )FR = G *4/3πR * dmdividing both sides of the equation0.3 = ( R - h ) / Rtherefore :h = 0.7 RHence we can conclude that A) If we move the apple0.3 FR awayfrom the planet the value of h is0.825 Rand If we move the apple0.3 FR intothe tunnel the distance is ;0.7 RLearn more aboutplanet surface:brainly.com/question/23661578...

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