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As the drawing illustrates, two disks with masses m1 and m2 are moving horizontally to the right at a speed of v0. They are on an airhockey table, which supports them with an essentially frictionless cushion of air. They move as a unit, with a compressed spring between them, which has a negligible mass. Then the spring is released and allowed to push the disks outward. Consider the situation where disk 1 comes to a momentary halt shortly after the spring is released. Assuming that m1 = 1.1 kg, m2 = 2.3 kg, and v0 = + 4.1 m/s, find the velocity of disk 2 at that moment.
As the drawing illustrates, two disks with masses m1 and m2 are moving horizontally to the right at a speed of v0. They are on an airhockey table, which supports them with an essentially frictionless cushion of air. They move as a unit, with a compressed spring between them, which has a negligible mass. Then the spring is released and allowed to push the disks outward. Consider the situation where disk 1 comes to a momentary halt shortly after the spring is released. Assuming that m1 = 1.1 kg, m2 = 2.3 kg, and v0 = + 4.1 m/s, find the velocity of disk 2 at that moment.
Final answer:Thevelocityofdisk 2at the moment when disk 1 comes to a momentary halt is approximately 4.1 m/s.Explanation:When thespringis released, the force exerted by the spring on disk 1 causes it to decelerate until it comes to amomentary halt. At the same time, the force exerted by the spring ondisk 2causes it to accelerate.According to the principle ofconservation of momentum, the total momentum of an isolated system remains constant if no external forces act on it. In this case, the system consists of the two disks.Before the spring is released, the total momentum of the system is given by:Initial momentum = m1 * v0 + m2 * v0After disk 1 comes to a momentary halt, itsvelocityis 0. Therefore, the total momentum of the system after the spring is released is:Final momentum = 0 + m2 * v2According to the principle of conservation of momentum, the initial momentum and the final momentum must be equal:m1 * v0 + m2 * v0 = 0 + m2 * v2Simplifying the equation, we can solve for v2:v2 = (m1 * v0 + m2 * v0) / m2Substituting the given values, we have:v2 = (1.1 kg * 4.1 m/s + 2.3 kg * 4.1 m/s) / 2.3 kgSolving the equation, we find:v2 ≈ 4.1 m/sLearn more aboutvelocityhere:brainly.com/question/31730199#SPJ14...