Solved:

Checkmark

Answered by AI, Verified by Human Experts

.

.Analyze the following code:

public class Test {
public static void main(String[] args) {
int[] x = new int[5];
int i;
for (i = 0; i < ; i++)
x[i] = i;
System.out.println(x[i]);
}
}
(a) The program displays 0 1 2 3 4
(b) The program displays 4
(c) The program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException
(d) The program has syntax error because i is not defined in the last statement in the main method
(e) The program displays 1 2 3 4 5.

Final answer:The code has a syntax error due to a missing condition in the 'for loop'. If corrected, it would lead to a runtime error because the index would be out of bounds when 'System.out.println' is called.Explanation:Analyzing the code provided, we can observe that it is a Java program that initializes an array with five elements and attempts to assign values to each element in a for loop. However, there is missing condition in the loop which will lead to asyntax error, preventing the program from compiling. If the missing condition in the loop were corrected to 'i < 5', the program would still result in a runtime error, specifically an ArrayIndexOutOfBoundsException, because after the loop, 'i' would be incremented to 5 and there is no index '5' in the array (since array indices start from 0)....

Unlock full access for 72 hours, watch your grades skyrocket.
For just $0.99 cents, get access to the powerful quizwhiz chrome extension that automatically solves your homework using AI. Subscription renews at $5.99/week.