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An unknown compound, believed to be a hydrocarbon, showed the following behavior: it burned with yellow sooty flame; no heat Or color appeared when sulfuric acid was added; permanganate solution remained purple; the red color of bromine solution was lost only after catalyst was added. From the compounds below, circle the one that fits the observations Write equations for the tests that work: CH;CH,CH;CHzCH; H-C=C -CH,CHzCH: 299
An unknown compound, believed to be a hydrocarbon, showed the following behavior: it burned with yellow sooty flame; no heat Or color appeared when sulfuric acid was added; permanganate solution remained purple; the red color of bromine solution was lost only after catalyst was added. From the compounds below, circle the one that fits the observations Write equations for the tests that work: CH;CH,CH;CHzCH; H-C=C -CH,CHzCH: 299
Thealkenethat fits the behavior described is H-C=C-CH2-CH=CH2 (2-butene).Based on the observations given, we can identify the unknown compound as an alkene. Alkenes arehydrocarbonsthat contain a carbon-carbon double bond. Here's how each observation matches the behavior of an alkene:1. Burning with a yellow sooty flame: When hydrocarbons burn, they produce a flame. The yellow and sooty flame indicates the presence of unsaturated carbon-carbon bonds, which is characteristic of alkenes.2. No heat or color change whensulfuric acidis added: Alkenes are generally unreactive with sulfuric acid. This is because the carbon-carbon double bond is relatively stable and does not readily react with the acid.3.Permanganatesolution remains purple: Potassium permanganate (KMnO4) is a strong oxidizing agent. Alkenes are oxidizable and can react with KMnO4 to produce a color change, turning the purple solution to colorless.4. The red color of bromine solution is lost only aftercatalystis added: Bromine (Br2) is a reddish-brown liquid that reacts with alkenes. In the absence of a catalyst, the reaction is slow or may not occur at all.However, when a catalyst is added, such asbrominewater with an acid catalyst, the red color of bromine is lost as it reacts with the alkene. Based on these observations, the alkene that fits the behavior described is H-C=C-CH2-CH=CH2 (2-butene).This alkene exhibits all the observed characteristics. Please note that this is a direct answer to the question, providing the specific alkene that fits the observations.To know more aboutalkene, visit:brainly.com/question/33961521#SPJ11...