Solved:
Answered by AI, Verified by Human Experts
An object with weight W is dragged along a horizontal plane by a force acting along a rope attached to the object. If the rope makes an angle θ with a plane, then the magnitude of the force is F = μW μ sin(θ) + cos(θ) where μ is a constant called the coefficient of friction. For what value of θ is F smallest?
An object with weight W is dragged along a horizontal plane by a force acting along a rope attached to the object. If the rope makes an angle θ with a plane, then the magnitude of the force is F = μW μ sin(θ) + cos(θ) where μ is a constant called the coefficient of friction. For what value of θ is F smallest?
Themagnitudeof the force,F, is varies with theanglethe rope makeswith theplane accordingto the givenequations.Fwill be smallest when.Reason:The givenparametersare;Angle the rope makes with theplane= θThemagnitudeof the force is,The value ofθfor which the value ofFis smallest.Solution;When,Fissmallest, we have;Therefore;-μ·W·(μ·cos(θ) - sin(θ))μ·cos(θ) = sin(θ)Bysymmetric property, we have;sin(θ) = μ·cos(θ)Which gives;θ =arctan(μ)Therefore;F, will be smallest when.Learn more here:brainly.com/question/14457114Question; The given equation of the magnitude of the force in relation to the angle the rope makes with the plane, θ, is presented as follows;...
Unlock full access for 72 hours, watch your grades skyrocket.
For just $0.99 cents, get access to the powerful quizwhiz chrome extension that automatically solves your homework using AI. Subscription renews at $5.99/week.