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Air contained within a piston-cylinder assembly is slowly heated. During this process the pressure first increases linearly with volume where p1 = 100 kPa, p2 = 450 kPa, V1 = 0.4 m3 and V2 = 1.5 m^3. After this initial change the pressure is constant at 450 kPa and the volume expands to 2.1m^3. Determine the total work done in kJ.
Air contained within a piston-cylinder assembly is slowly heated. During this process the pressure first increases linearly with volume where p1 = 100 kPa, p2 = 450 kPa, V1 = 0.4 m3 and V2 = 1.5 m^3. After this initial change the pressure is constant at 450 kPa and the volume expands to 2.1m^3. Determine the total work done in kJ.
Final answer:The total work done by the air within a piston-cylinder assembly during heating is found by adding the work done during the linear pressure increase and the isobaric expansion, calculated separately.Explanation:To determine the total work done by the air within a piston-cylinder assembly during a heating process that involves both linear and isobaric volume expansions, we break the process into two parts.Part 1: Linear Pressure IncreaseInitially, the pressure increases linearly from p1 = 100 kPa to p2 = 450 kPa as the volume expands from V1 = 0.4 m3 to V2 = 1.5 m3. The work done during this process can be calculated as the area under the process curve on a P-V diagram, which is a trapezoid. Therefore, the formula used is:Work1= (1/2) * (p1 + p2) * (V2 - V1)Part 2: Isobaric ExpansionAfter the initial change, the volume further expands to V3 = 2.1 m3 at constant pressure p3 = 450 kPa. The work done in this isobaric process is given by:Work2= p3 * (V3 - V2)The total work done by the air is the sum ofWork1andWork2, calculated in kilojoules (kJ)....