A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 89m long and 66m wide. Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

Question

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 89m long and 66m wide. Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

Accepted Answer

The area of the field will be given by:Area=[area of the semi circle]+[area of rectangle]Area of semicircle is given by:Area=πr^2where;radius,r=66/2=33 mthus;Area=3.14*33^23,419.46 m^2The area of the rectangle is given by:Area=89*66=5,874 m^2Hence the area of the field will be:A=(5,874)+(3,419.46)A=9,293.46 m^2

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A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 89m long and 66m wide. Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 89m long and 66m wide. Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.