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Given,The initial speed, u=20.00 m/sThe distance between the submerine and the target is d=2000.0mThe sound of impact is heard after T=101.4 s.To findThe speed of sound in water.ExplanationHere the total time taken to reach the submarine is the sum of thetime taken by the torpedo to reach the target and the time taken for it to come back.Let the speed be v.Thus,ConclusionSpeed of the sound in water is1428.6 m/s...