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A tension test was performed on a steel specimen having an original diameter of 0.503 in. and gauge length of 2.00 in. The data is listed in the table below. (Figure 1)
A tension test was performed on a steel specimen having an original diameter of 0.503 in. and gauge length of 2.00 in. The data is listed in the table below. (Figure 1)no title provided
Determine approximately the modulus of elasticity. E =
Determine approximately the yield stress. ?Y =
Determine approximately the ultimate stress. ?u =
Determine approximately the rupture stress. ?R =
Express all answers to two significant figures and include appropriate units.
The following approximate values are given for themodulusof elasticity: E = 29,000 ksi (or 200 GPa), Y = 45 ksi (or 310 MPa), u = 67 ksi (or 460 MPa), and R = 63 ksi (or 430 MPa).What gauge length should be used to test a steel specimen's tensile strength?Using anextensometerwith a gauge length of 45 mm, the elongation was measured during the tensile test. The tensile testing samples are 5 mm thick, 20 mm broad, with a fillet radius of 25 mm, and 100 mm in gauge length. They are removed from the weld's transverse direction.Exists a formula for creating tension?Solution: We are aware that T = mg + ma is the formula used to compute the force oftension.To know more aboutmodulusvisit:-brainly.com/question/13261401#SPJ1...