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A tennis ball on Mars, where the acceleration due to gravity is 0.379 g and air resistance is negligible, is hit directly upward and returns to the same level 6.20 s later.a) How high above its original point did the ball go?b) How fast was it moving just after being hit?
A tennis ball on Mars, where the acceleration due to gravity is 0.379 g and air resistance is negligible, is hit directly upward and returns to the same level 6.20 s later.a) How high above its original point did the ball go?b) How fast was it moving just after being hit?
Final answer:The initial velocity and the maximum height of a tennis ball hit on Mars is calculated using principles of uniform motion under gravity, taking into account mars' gravitational acceleration. The velocity is calculated using the equation for time of flight and the max height using the equation for distance travelled under constant acceleration.Explanation:The subject of this question is the calculation of height and initial speed of atennis ballhit on Mars' surface using basic physics principles. Firstly, we can use the equation for the time of flight of an object under uniform acceleration, which is t = 2v/g where v is the initial velocity and g is the acceleration due to gravity, to find the initial velocity.OnMars, theacceleration due to gravityis 0.379g, where g is the acceleration due to gravity on earth, or 3.71 m/s². Using the given time of 6.20s we can solve for v, which will be the initial speed of the tennis ball.Secondly, to find the maximum height the ball reached, we can use the equation for distance travelled under constant acceleration, which is d = v²/g. This will give us the maximum height reached above its original point.Learn more about Physics of motion under gravity here:brainly.com/question/36922560#SPJ12...