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A tank originally contains 100 gallon of fresh water. Then water containing 0.5 Lb of salt per gallon is pourd into the tank at a rate of 2 gal/minute, and the mixture is allowed to leave at the same rate. After 10 minute the process is stopped, and fresh water is poured into the tank at a rate of 2 gal/min, with the mixture again leaving at the same rate. Find the amount of salt in the tank at end of an additional 10 minutes.
A tank originally contains 100 gallon of fresh water. Then water containing 0.5 Lb of salt per gallon is pourd into the tank at a rate of 2 gal/minute, and the mixture is allowed to leave at the same rate. After 10 minute the process is stopped, and fresh water is poured into the tank at a rate of 2 gal/min, with the mixture again leaving at the same rate. Find the amount of salt in the tank at end of an additional 10 minutes.
Final answer:In 10 minutes, 10 lb of salt enters and leaves thetank, resulting in 0 lb of salt in the tank.Explanation:To find the amount of salt in the tank at the end of an additional 10 minutes, we need to determine the amount of salt that enters and leaves the tank during this time.First, let's calculate the amount of salt that enters the tank in 10 minutes. Using the rate of 2 gal/minute and the concentration of 0.5 lb/gal, we can calculate:Amount of salt entering = 2 gal/min * 0.5 lb/gal * 10 min = 10 lbNext, let's calculate the amount of salt that leaves the tank in 10 minutes. Since fresh water is being poured into the tank at a rate of 2 gal/min, the mixture is being replaced at the same rate. Therefore, theamountof salt leaving the tank is equal to the amount of salt that entered:Amount of salt leaving = 10 lbFinally, to find the amount of salt in the tank at the end of the additional 10 minutes, we subtract the amount of salt that left from the amount of salt that entered:Amount of salt in the tank = Amount of salt entering - Amount of salt leaving = 10 lb - 10 lb = 0 lbLearn more about amount of salt in the tank here:brainly.com/question/38535559#SPJ2...