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xCM, yCM = 0, -3.27 m are thecoordinatesof the center of mass of the loaded ferryboat relative to the center of the raft.To find the coordinates of thecenterof mass (CM) of the loaded ferryboat, we need to consider themassandpositionof the raft and the three cars. We will use the following formulas for finding the x and y coordinates of the center of mass:xCM = (Σ mi * xi) / Σ miyCM = (Σ mi * yi) / Σ miwhere mi is the mass of each object and xi and yi are their respective x and y coordinates.Determine the coordinates of the raft and the cars- The raft's center (origin): (0, 0)- NE corner car: (9, 9)- SE corner car: (9, -9)- SW corner car: (-9, -9)Calculate xCMxCM = (7100 * 0 + 1350 * 9 + 1350 * 9 + 1350 * (-9)) / (7100 + 1350 + 1350 + 1350)xCM = (0 + 12150 - 12150) / (11150)xCM = 0 mCalculate yCMyCM = (7100 * 0 + 1350 * 9 + 1350 * (-9) + 1350 * (-9)) / (11150)yCM = (12150 - 12150 - 12150) / (11150)yCM = -3.27 mSo, the coordinates of the center of mass of the loaded ferryboat relative to the center of the raft are:xCM, yCM = 0, -3.27 mMore oncoordinates:brainly.com/question/17117535#SPJ11...