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A small spherical insulator of mass 6.68 x 10^-2 kg and charge +0.600 C is hung by a thin wire of negligible mass. A charge of -0.900 C is held 0.150 m away from the sphere and directly to the right of it, so the wire makes an angle with the vertical (see the drawing). Find (a) the angle and (b) the tension in the wire.
A small spherical insulator of mass 6.68 x 10^-2 kg and charge +0.600 C is hung by a thin wire of negligible mass. A charge of -0.900 C is held 0.150 m away from the sphere and directly to the right of it, so the wire makes an angle with the vertical (see the drawing). Find (a) the angle and (b) the tension in the wire.
Final answer:To find the angle and tension in the wire, we can use the concept of electrostatic force and Coulomb's Law.Explanation:To find the angle and tension in the wire, we can use the concept of electrostatic force. The electrostatic force between the two charges can be calculated using Coulomb's Law:FE = k * (q1 * q2) / r^2where FE is the electrostatic force, k is the electrostatic constant (8.99 x 10^9 N·m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.By equating this force to the tension in the wire and solving for the angle, we can find the angle:tan(angle) = FE / Twhere T is the tension in the wire....
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