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A slice of pizza has 500 kcal. If the pizza is burned and its heat is used to warm a 50-L container of cold water, what would be the approximate increase in the temperature of the water? (Note: A liter of cold water weighs about 1 kg).
A slice of pizza has 500 kcal. If the pizza is burned and its heat is used to warm a 50-L container of cold water, what would be the approximate increase in the temperature of the water? (Note: A liter of cold water weighs about 1 kg).
Given:The heat content of the pizza is Q = 500 kcalThe volume of the cold water is V = 50 LThe mass of a liter of cold water is 1 kg.Calculate the mass, M, of cold water.M = (50 L)*(1 kg/L) = 50 kgThe specific heat of water isc = 4.184 kJ/(kg-K)Also,1 kcal = 4184 J, thereforeQ = (500 kcal)*(4184 J/kcal) = 2.092 x 10⁶ JLet ΔT = increase in temperature of the cold water, °C (same as K).ThenQ = M*c*ΔTorΔT = Q/(M*c)Answer: The temperature increases by 10 °C (or 10 K)...
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