Final answer:The minimum volume of the ice slab on which a 45.0 kg woman can stand without getting wet can be calculated by dividing her mass (45.0 kg) by the density of water (1,000 kg/m³). However, this calculation assumes that the entire volume of the ice slab is submerged, and doesn't account for the fact that some parts of the slab may be above water.Explanation:This problem can be solved by applying the principles ofdensityand buoyancy. When the woman stands on the ice, the ice must displace an amount of water equivalent to her weight in order for her not to sink. Ice floats because its density is less than that of water. The minimum volume of the ice slab can be computed using the formula:V = m / ρwhere V is volume, m is mass, and ρ is the density of water. Given the woman's mass (45.0 kg) and the density of water (approximately 1,000 kg/m³), we can calculate the minimum volume required for the ice slab to support the woman.It's important to note that the calculation assumes the entire volume of the ice slab is submerged in water. If the slab is less dense than water, some part of it will be above water, which would mean the actual volume of the slab would need to be slightly larger than the minimum volume calculated.Learn more about Buoyancy here:brainly.com/question/36883204#SPJ12...

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