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Thelengthof the inclinedplaneis 63.53 m and thetimetaken by theskierto cover thedistanceis 7.0588 sec.Given to usVelocity, u = 3.0 m/sAngle of Inclination = 10"Velocity of skier at the bottom, v = 15 m/sWhat is the acceleration of the skier on the inclined plane?We know that acceleration of theskieron theinclinedplane can be given as,a = g sin(θ)a = g sin(10)a= 9.81 x 0.1736a = 1.70 m/sec²What is the length of the incline?We know that according to thethird equationofmotionSubstitute the values,How long does it take him to reach the bottom?Using thefirst equationofmotion,Hence, thelengthof the inclined plane is63.53 mand the time taken by theskierto cover thedistanceis7.0588 sec.Learn more aboutMotion:brainly.com/question/11049671...