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A simple pendulum consists of a bob of mass 1.8 kg attached to a string of length 2.3 m. The pendulum is held at an angle of 30 degrees from the vertical of by a light horizontal string attached to a wall.

A simple pendulum consists of a bob of mass 1.8 kg attached to a string of length 2.3 m. The pendulum is held at an angle of 30 degrees from the vertical of by a light horizontal string attached to a wall.(a) On the figure attached, draw a free-body diagram showing and labeling the forces on the bob.
(b) Calculate the tension in the horizontal string.
(c)The horizontal string is now cut close to the bob and the pendulum swings down. Calculate the speed of the bob at its lowest position.

Thetensionin the horizontalstringis 9.04 N. The speed of the bob at its lowest position is 2.96 m/s.(a) A free-body diagram for the bob includes:1. Gravitational force (mg) acting vertically downward2. Tension in thependulumstring (T1) acting along the string towards the pivot point3. Tension in the horizontal string (T2) acting horizontally towards the wall(b) To calculate the tension in the horizontal string (T2):Step 1: Find the components of thegravitational force(mg) along and perpendicular to the pendulum string.Step 2: Equate the horizontal component of mg to T2, since there's no horizontal acceleration.(c) To calculate thespeedof the bob at its lowest position:Step 1: Find the initial gravitational potential energy of the bob (mgh).Step 2: At the lowest position, all thepotentialenergy is converted into kinetic energy (1/2 mv^2).Step 3: Solve for v (speed) using the conservation of energy principle.Learn more abouttensionhere:brainly.com/question/31260973#SPJ11...

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