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Thetensionin the horizontalstringis 9.04 N. The speed of the bob at its lowest position is 2.96 m/s.(a) A free-body diagram for the bob includes:1. Gravitational force (mg) acting vertically downward2. Tension in thependulumstring (T1) acting along the string towards the pivot point3. Tension in the horizontal string (T2) acting horizontally towards the wall(b) To calculate the tension in the horizontal string (T2):Step 1: Find the components of thegravitational force(mg) along and perpendicular to the pendulum string.Step 2: Equate the horizontal component of mg to T2, since there's no horizontal acceleration.(c) To calculate thespeedof the bob at its lowest position:Step 1: Find the initial gravitational potential energy of the bob (mgh).Step 2: At the lowest position, all thepotentialenergy is converted into kinetic energy (1/2 mv^2).Step 3: Solve for v (speed) using the conservation of energy principle.Learn more abouttensionhere:brainly.com/question/31260973#SPJ11...