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A rock thrown with speed 11.5m/s and launch angle 30.0?(above the horizontal) travels a horizontal distance of d = 20.0m before hitting the ground. From what height was the rock thrown? Use the value g = 9.810m/s2 for the free-fall acceleration.Find the height yi from which the rock was launched.
A rock thrown with speed 11.5m/s and launch angle 30.0?(above the horizontal) travels a horizontal distance of d = 20.0m before hitting the ground. From what height was the rock thrown? Use the value g = 9.810m/s2 for the free-fall acceleration.Find the height yi from which the rock was launched.
Answer:The rock was launched from approximatelyabove the ground. Assume that the air resistance on the rock is negligible.Explanation:It is given that the initial velocityis atabove the ground. Therefore:Initial horizontal velocity would be:.Initial vertical velocity would be:.Under the assumptions, horizontal velocity would stay the same during the entire flight:.Since the rock travelled a horizontal distance of, the duration of the flight would be:.Also under the assumptions, vertical acceleration of the rock would beduring the entire flight. (Negative since gravitational pull points towards the ground.)Apply the SUVAT equation to find thevertical displacementof the rock (distance between where the rock was launched and where the rock landed):.(Negative since the rock landed below where it was launched.)In other words, the rock was launched from a height of approximately....