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A proton, traveling with a velocity of 4.5 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.0 × 10−14 N and a direction of due south. What are the magnitude and direction of the magnetic field causing the force?
A proton, traveling with a velocity of 4.5 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.0 × 10−14 N and a direction of due south. What are the magnitude and direction of the magnetic field causing the force?
Answer:Magnetic field, B = 0.11 i (in k direction)Explanation:It is given that,Velocity of the proton,Magnetic force,(due south)The magnetic force acting on the electron is given by :(-j) = (i) × (B)q is the charge on protonB = 0.11So, the magnitude of 0.11 T is acting on the proton in and is acting directed upward above the plane. Hence, this is the required solution....
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