Aprojectilefired vertically from Earth's surface with an initialspeedof 5.6 km/s, neglecting air drag, will reach a maximum height of approximately 15,926,530.61 meters above the surface of the Earth.When a projectile is fired vertically from Earth's surface, it will experience the force of gravity acting in the opposite direction of its initialvelocity. As a result, the projectile will slow down until it reaches its maximum height. At this point, the velocity of the projectile becomes zero.The maximum height reached by a projectile fired vertically from Earth's surface can be determined using the equation:h = (v²) / (2g)where:h is the maximum height,v is the initial speed of the projectile, andg is the acceleration due to gravity.Given that the initial speed of the projectile is 5.6 km/s, we need to convert it to m/s by multiplying it by 1000:v = 5.6 km/s * 1000 m/km= 5600 m/sTheacceleration due to gravityon Earth is approximately 9.8 m/s².Using the equation, we can calculate the maximum height:h = (5600 m/s)² / (2 * 9.8 m/s²)= 15926530.612244898 mSo, the projectile will go approximately 15,926,530.61 meters above the surface of the Earth.Therefore, neglectingair drag, the projectile will go approximately 15,926,530.61 meters above the surface of the Earth.In conclusion, a projectile fired vertically from Earth's surface with an initial speed of 5.6 km/s, neglecting air drag, will reach a maximum height of approximately 15,926,530.61 meters above the surface of the Earth.To know more aboutvelocityvisit:brainly.com/question/34025828#SPJ11...

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