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A positron undergoes a displacement ∆r= 2i -3j+6k, ending with the position vector r= 3j-4k, in meters. what was the positron's initial position
A positron undergoes a displacement ∆r= 2i -3j+6k, ending with the position vector r= 3j-4k, in meters. what was the positron's initial position
Final answer:Theinitial positionof the positron is determined by subtracting the displacement vector from the final position vector, yielding a result of 2i + 6j - 2k meters.Explanation:The initial position of the position can be calculated using the given final position anddisplacementvectors. According to vector addition, the final position vector r is equal to the initial position vector plus the displacement vector ∆rSo, if we rearrange we have, Initial position vector = Final position vector - Displacement vector. Therefore, the initial positionvectorwill be r - ∆r = (3j - 4k) - (2i - 3j + 6k).So, solving this equation, the initial position of the positron turns out to be 2i + 6j - 2kmeters.Learn more about Initial Position here:brainly.com/question/33914702#SPJ2...