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Thevelocityat the end of 2.28 s is -4.805 m/s. The negative sign shows that the ball is falling downwhile approaching the crossbar.Thetimeto travel 36 m is given byt = 36 / 23.6 cos 48 = 2.28 s.In this time it travels a verticalheightgiven byh = 23.6 sin 48*2.28 – ½ * 9.8 *2.28^2h =14.507 mSince 14.507 m is more than 3.05 mthe ball is above the crossbar by a height of 0.89.The velocity at the end of 2.28 s isv = u –gt = 23.6 sin 48 – 9.8*2.28 = -4.805 m/sTherefore, the negative sign shows that the ball is falling downwhile approaching the crossbar.To know more aboutvelocity:brainly.com/question/34025828#SPJ12...