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A person pushes horizontally with a force of 220N on a 55kg crate to move it across a level floor. The coefficient of kinetic friction between the crate and the floor is 0.35. What are the magnitude of the frictional force
A person pushes horizontally with a force of 220N on a 55kg crate to move it across a level floor. The coefficient of kinetic friction between the crate and the floor is 0.35. What are the magnitude of the frictional force
Final Answer:The magnitude of thefrictional forceis 188.84 N.Explanation:To find the magnitude of the frictional force, we can use the equation:Frictional Force (F_friction) =Coefficientof Friction (μ) × Normal Force (F_normal)First, we need to calculate the normal force. When the crate is on a level floor and not accelerating vertically, the normal force is equal to the weight of the crate, which can be calculated as:Weight(F_weight) = Mass (m) × Acceleration due to gravity (g)F_weight = 55 kg × 9.81 m/s² ≈ 539.55 NSo, the normal force is 539.55 N. Now, we can find the frictional force:F_friction = 0.35 × 539.55 N ≈ 188.84 NTherefore, themagnitudeof the frictional force is approximately 188.84 N.Learn more aboutfrictional forcebrainly.com/question/13707445#SPJ11...