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A person pushes a 14.0-kg lawn mower at constant speed with a force of F=88.0 N directed along the handle, which is at an angle of 45.0° to the horizontal. (a) Draw the free-body diagram showing all forces acting on the mower.

A person pushes a 14.0-kg lawn mower at constant speed with a force of F=88.0 N directed along the handle, which is at an angle of 45.0° to the horizontal. (a) Draw the free-body diagram showing all forces acting on the mower.

1) The horizontalfriction force(F_friction) is equal in magnitude and opposite in direction to the applied force will be 89.0 N. 2) The normal force is also 157.0 N, acting vertically upward. 3) The person must exert a force of 10.24 N to accelerate the lawn mower under the given conditions, assuming the same friction force.Let's address each part of the problem step by step:Free-Body Diagram:To draw thefree-body diagramfor the lawn mower, we need to represent all the forces acting on it. The forces include:The applied force by the person (pushing force), which is at an angle of 45.0 degrees to the horizontal.The weight of the lawn mower acting vertically downward.Thenormal forceexerted by the ground on the mower, which is also vertical.Calculate the Horizontal Friction Force:Since the lawn mower is moving at a constant speed, it's not accelerating, which means the net force on it is zero. Theapplied forceby the person must balance the friction force to maintain constant speed. The horizontal friction force (F_friction) is equal in magnitude and opposite indirectionto the applied force:F_friction = F_applied = 89.0 NCalculate the Normal Force:The normal force (N) is the force exerted by the ground on the lawn mower in thevertical direction. It balances the weight of the lawn mower. The weight (W) is given by:W = mgWhere:m = 16.0 kg (mass of the lawn mower)g = 9.81 m/s² (accelerationdue to gravity)W = 16.0 kg x 9.81 m/s² = 157.0 NSo, the normal force is also 157.0 N, acting vertically upward.Force to Accelerate the Mower:To accelerate the lawn mower from rest to 1.6 m/s in 2.5 seconds, you can useNewton's second law:F = maWhere:F is the net force required.m is the mass of the lawn mower (16.0 kg).a is the acceleration (which you can find from the change invelocityand time).a = (v_final - v_initial) / ta = (1.6 m/s - 0 m/s) / 2.5 s = 0.64 m/s²Now, use Newton's second law:F = (16.0 kg) x (0.64 m/s²) = 10.24 NSo, the person must exert aforceof 10.24 N to accelerate the lawn mower under the given conditions, assuming the same friction force.To know more aboutfriction forceherebrainly.com/question/34015822#SPJ1--The given question is incomplete, the complete question is"A person pushes a 16.0kg lawn mower at constant speed with a force of 89.0N directed along the handle, which is at an angle of 45.0 degrees to the horizontal. 1) Draw the free-body diagram showing all forces acting on the mower. 2) Calculate the horizontal friction force on the mower. 3) Calculate the normal force exerted vertically upward on the mower by the ground. 4)What force must the person exert on the lawn mower to accelerate it from rest to 1.6m/s in 2.5 seconds, assuming the same friction force?"--...

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