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A machinist creates a solid steel part for a wind turbine. The part has a volume of 1015 cubic centimeters. Steel can be purchased for $0.29 per gram, and has a density of 0.795 g/cm3. If the machinist makes 500 of these parts, what is the cost of the steel, to the nearest dollar
A machinist creates a solid steel part for a wind turbine. The part has a volume of 1015 cubic centimeters. Steel can be purchased for $0.29 per gram, and has a density of 0.795 g/cm3. If the machinist makes 500 of these parts, what is the cost of the steel, to the nearest dollar
Final answer:The cost of the steel for producing 500 parts for a wind turbine is calculated using the volume of a part, the density of steel, and the cost per gram, resulting in a total cost of $117077 to the nearest dollar.Explanation:The cost of the steel for making 500 parts for a wind turbine can be calculated by first determining the mass of a single steel part, multiplying that by the number of parts, and then applying the cost per gram of steel. The density of steel is given as 0.795 g/cm3, and the volume of the part is 1015 cm3. Thus, a single part's mass is calculated by density times volume, which is 0.795 g/cm3 imes 1015 cm3 = 807.425 g. Multiplying this by the number of parts (500), we get the total mass of steel: 807.425 g/part imes 500 parts = 403712.5 g. Finally, to find the total cost, we multiply the total mass by the cost per gram: 403712.5 g imes $0.29/g = $117076.625, which rounds up to $117077 when expressed to the nearest dollar....