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A galvanic cell is powered by the following redox reaction: 2 Cu + 2 (aq) + H 2 (g) + 2 OH − (aq) → 2 Cu + (aq) + 2 H 2 O (l)
A galvanic cell is powered by the following redox reaction: 2 Cu + 2 (aq) + H 2 (g) + 2 OH − (aq) → 2 Cu + (aq) + 2 H 2 O (l)a. cathode half reaction
b. anode half reaction
c. cell voltage in standard conditions
The anodehalf-reactionis 2Cu(s) → 2Cu2+(aq) + 4e- and the cathode half-reaction is H2(g) + 2OH-(aq) + 2e- → 2H2O(l).The cell voltage in standard conditions for the given redox reaction is-0.34V.Agalvanic cellis a device that converts chemical energy into electrical energy through aredox reaction. Two half-cells are present in a galvanic cell, one anode (where oxidation occurs) and one cathode (where reduction occurs). The anode half-reaction is 2Cu(s) → 2Cu2+(aq) + 4e- and the cathode half-reaction is H2(g) + 2OH-(aq) + 2e- → 2H2O(l).The net reaction of the galvanic cell is the sum of the two half-reactions, which yields the balanced chemical equation:2Cu(s) + 2H2(g) + 2OH-(aq) → 2Cu2+(aq) + 2H2O(l)The cell voltage in standard conditions is the difference in potential energy between the anode andcathode. The standard reduction potential for the cathode half-reaction is 0V, while the standard reduction potential for the anode half-reaction is +0.34V. As a result, the overall voltage of the cell is determined by subtracting the anode potential from the cathode potential:0V - (+0.34V) = -0.34VThus, the cell voltage in standard conditions for the given redox reaction is-0.34V.learn more aboutgalvanic cellRefer:brainly.com/question/29784730#SPJ11...