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A circular-motion addict of mass 80 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.1 m/s. (a) What is the period of the motion? What is the magnitude of the normal force on the addict from the seat when both go through (b) the highest point of the circular path and (c) the lowest point?
A circular-motion addict of mass 80 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.1 m/s. (a) What is the period of the motion? What is the magnitude of the normal force on the addict from the seat when both go through (b) the highest point of the circular path and (c) the lowest point?
Final answer:Explanation of period of motion, normal force at highest and lowest points on a Ferris wheel ride.Explanation:The period of the motion:To find the period of the motion, we can use the formula T = 2πr/v, where r = radius and v = speed. Substituting the values, T = 2π(10m)/(6.1m/s) ≈ 4.09 seconds.Normal force at the highest point: At the highest point, the normal force is given by N = mg - mv^2/r, where g is the acceleration due to gravity. Substituting the values, N =≈ 392N.Normal force at the lowest point: At the lowest point, N = mg + mv^2/r. Substituting the values,N =≈ 1088N....
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