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A bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. find the probability. one of each flavor

A bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. find the probability. one of each flavor

Therequiredprobabilityfor the givencaseis 0.218.What is probability?Probabilityis thebranchof Mathematics that deals with themeasurementof thechanceof occurrence of a random event.The probability of anyeventalwaysliesin theclose intervalof 0 and 1 [0,1].Thezerovalue of probabilityindicatesthat the event will not happen while its valueequaltooneindicate that it will happen.Given that,Thenumberof cherry, orange and lemoncandiesare 6, 3 and 2 respectively.Then,total numberof candies is 6 + 3 + 2 = 11.The total number ofwaysof selecting 3piecesout of the 11 is ¹¹C₃.The number of ways of selectingcherry candyis ⁶C₁ = 6The number of ways of selectingorangecandy is ³C₁ = 3And, the number of ways of selectinglemoncandy is ²C₁ = 2.Hence, the required probability can be given as theratioof theproductof getting each of thecandiesto the total number of ways as follows,P(3 pieces of each flavor) = (6 × 3 × 2)/¹¹C₃= 36/165= 0.218Hence, theprobabilityof getting 3candiesofeach flavoris 0.218.To know more aboutprobabilityclick on,brainly.com/question/11234923#SPJ5...

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