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A 1,200-kilogram car traveling at 10 meters per second hits a tree and is brought to rest in 0.10 second. What is the magnitude of the average force acting on the car to bring it to rest? A. 1.2 × 10² N B. 1.2 × 10³ N C. 1.2 × 10⁴ N D. 1.2 × 10⁵ N
A 1,200-kilogram car traveling at 10 meters per second hits a tree and is brought to rest in 0.10 second. What is the magnitude of the average force acting on the car to bring it to rest? A. 1.2 × 10² N B. 1.2 × 10³ N C. 1.2 × 10⁴ N D. 1.2 × 10⁵ N
Final answer:The magnitude of theaverage forceacting on the car to bring it to rest is 120,000 N or 1.2 × 10^5 N.therefore the correct answer is dExplanation:To calculate the magnitude of the average force acting on the car, we can use the equation:F = m * aWhere F is the force, m is the mass of the car, and a is theacceleration.First, we need to calculate the acceleration of the car:a = (v_f - v_i) / tWhere v_f is the final velocity (0 m/s), v_i is the initial velocity (10 m/s), and t is the time taken for the car to come to rest (0.10 s).Plugging in the values, we get:a = (0 - 10) / 0.10 = -100 m/s^2Next, we can calculate the force:F = m * aPlugging in the values, we get:F = 1200 kg * -100 m/s^2 = -120,000 NSince force is a vector quantity, the magnitude of the force is given by its absolute value:|F| = |-120,000 N| = 120,000 NTherefore, the magnitude of the average force acting on the car to bring it to rest is 120,000 N, which is equivalent to 1.2 × 10^5 N. Therefore, the correct answer isD. 1.2 × 10^5 N.Learn more about Calculating force here:brainly.com/question/33703918#SPJ4...