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IE1(Rb) = 397.5

BE(Cl2) = 226

deltaHf(RbCl) = -431

Electron Affinity Cl = -332

a. -53.7

b. +53.7

C. -695

d. -808

e. +808

Final answer:The lattice energy for rubidiumchloride(RbCl) is calculated by substituting the given values into the equation derived from Hess's Law. The calculated lattice energy is found to be -695 kJ/mol.Explanation:In this question, you are asked to select the latticeenergyfor rubidium chloride (RbCl). The lattice energy can be calculated using various given energies including enthalpy of formation (ΔHf), electron affinity (Cl), enthalpy of sublimation, ionization energy, and bond dissociation energy. Using Hess's Law, this can be summed up as:ΔHf(RbCl) = [Sublimation Energy (Rb) +IonizationEnergy (Rb) + 0.5 × Bond Energy (Cl₂) + Electron Affinity (Cl)] - Lattice Energy (RbCl)By rearranging this formula, we find that the Lattice Energy (RbCl) = [SublimationEnergy (Rb) + Ionization Energy (Rb) + 0.5 × Bond Energy (Cl₂) + Electron Affinity (Cl)] - ΔHf(RbCl). Substituting in the given values, we find the lattice energy to be -695 kJ/mol. Therefore, the correct option is C. -695.Learn more about Lattice Energy here:brainly.com/question/34679410#SPJ12...

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