Final answer:The question concerns the reactions of nitric acid with potassium rubidium sulfide, and lead (II) nitrate with potassium iodide. The former reaction produces hydrogen sulfide gas, while the latter leads to the formation of a precipitate of lead iodide.Explanation:The question pertains to the chemical reactions involving precipitation and gas evolution. The two reactions described are:Nitric acid (HNO3) reacts with potassium rubidium sulfide to form hydrogen sulfide gas.Lead (II) nitrate (Pb(NO3)2) reacts with potassium iodide (KI) to form a precipitate of lead iodide (PbI2), while potassium nitrate (KNO3) remains in solution.These chemical reactions involve soluble and insoluble compounds as well as the creation of solids and gases during the reaction process. Applying solubility rules helps predict the formation of precipitates, such as lead iodide, which is insoluble and thus forms as a solid. When potassium iodide reacts with lead nitrate, a classic precipitation reaction occurs, showcasing an important principle in chemistry known as solubility rules....

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