a) The mechanism for theconversionof 1-butanol to 1-butyl bisulfate involves 2 steps.b) Bisulfate is a goodleaving groupforsubstitutionreactions, but it is not perfect.a) Mechanism for the conversion of1-butanolto 1-butyl bisulfateThe mechanism for the conversion of 1-butanol to1-butyl bisulfateis shown below.Step 1: Protonation of thehydroxylgroup[1-butanol] + H₂SO₄ → [1-butanol]⁺ + HSO₄⁻Step 2: Leaving group displacement[1-butanol]⁺ + HSO₄⁻ → 1-butyl bisulfate + H₂OThe first step involves theprotonationof the hydroxyl group of 1-butanol by sulfuric acid. This forms a positive charge on theoxygen atom, which makes it a good leaving group.In the second step, the sulfate ion fromsulfuric aciddisplaces the leaving group, water. This forms 1-butyl bisulfate, which is the product of the reaction.b.Bisulfateis a good leaving group for substitution reactions because it is a negatively charged ion. This means that it is relatively stable and does not have a strongtendencyto react with othernucleophiles. Additionally, the sulfate ion is relatively large, which makes it difficult for it to be stabilized by other atoms in the molecule.However, bisulfate is not a perfect leaving group. It is a relatively weak base, which means that it can beprotonatedby other acids. This can make it difficult to remove the bisulfate ion from the molecule. Additionally, the sulfate ion is a relativelybulky ion, which can make it difficult for it to leave the molecule.Overall, bisulfate is a good leaving group for substitution reactions, but it is not perfect. It is important to consider the properties of the bisulfate ion when designing a substitution reaction.Learn more aboutBisulfatefrom the link given below.brainly.com/question/31710098#SPJ4...

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