Solved:
Answered by AI, Verified by Human Experts
3. A 0.060 kg tennis ball traveling at 12 m/s is[returned by Venus. It leaves her racket with a velocity of
3. A 0.060 kg tennis ball traveling at 12 m/s is[returned by Venus. It leaves her racket with a velocity of35 m/s in the opposite direction from which it came.
a) what is the change in momentum of the tennis ball?
b) if the 0.060 kg ball is in contact with the racket for 0.02 s, what force was applied to the ball?
The initialmomentumof the ball is p₁ = m₁v₁ = (0.060 kg)(12 m/s) = 0.72 kg•m/s, and the final momentum of the ball is p₂ = m₂v₂ = (0.060 kg)(-35 m/s) = -2.1 kg•m/s. Therefore, the change in momentum is Δp = p₂ - p₁ = -2.1 kg•m/s - 0.72 kg•m/s = -2.82 kg•m/s.What is the law of conservation of momentum and how is it related to this problem?The law of conservation of momentum states that the total momentum of a closed system is conserved if there are noexternalforces acting on the system.In this problem, the system consists of the tennis ball and Venus' racket, and since there are no external forces acting on the system, the initial momentum of the ball must be equal to the final momentum of the ball andracketsystem.Why is the force calculated in part b negative?The forcecalculatedin part b is negative because it is in the opposite direction to themotionof the ball. The negative sign indicates that the force is acting in the direction opposite to the motion of the ball.To know more aboutmomentum,visit:brainly.com/question/30677308#SPJ1...