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29) A 2000 kg car is moving at 25 m/s when brakes are applied. If the average force exerted by the brakes is 5000 N, find the distance travelled by the car before it comes to rest?​

29) A 2000 kg car is moving at 25 m/s when brakes are applied. If the average force exerted by the brakes is 5000 N, find the distance travelled by the car before it comes to rest?​

Final answer:The car travels adistanceof 125 meters before it comes to rest.Explanation:To find the distance traveled by the car before it comes to rest, we can use the equation:F = maWhere F is the force exerted by the brakes, m is the mass of the car, and a is the acceleration. Rearranging the equation to solve foracceleration:a = F/mSubstituting the given values:a = 5000 N / 2000 kg = 2.5 m/s²Next, we can use the equation:v² = u² + 2asWhere v is the final velocity (0 m/s) and u is the initialvelocity(25 m/s). Rearranging the equation to solve for s:s = (v² - u²) / (2a)Substituting the given values:s = (0² - (25²)) / (2 × 2.5) = -625 / 5 = -125 mSince distance cannot be negative, we take the absolute value of the result:The car travels 125 meters before it comes to rest.Learn more aboutDistancehere:brainly.com/question/1566203#SPJ11...

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